Asked by Jackie Duran on Jun 04, 2024

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Write the equation of the line that passes through the point (0,87) \left( 0 , \frac { 8 } { 7 } \right) (0,78) and has slope m=32m = \frac { 3 } { 2 }m=23 . Write the equation in slope-intercept form.

A) y=32x−87y = \frac { 3 } { 2 } x - \frac { 8 } { 7 }y=23x78
B) y=87x+32y = \frac { 8 } { 7 } x + \frac { 3 } { 2 }y=78x+23
C) y=87x−32y = \frac { 8 } { 7 } x - \frac { 3 } { 2 }y=78x23
D) y=32x+87y = \frac { 3 } { 2 } x + \frac { 8 } { 7 }y=23x+78
E) y=16x+21y = 16 x + 21y=16x+21

Slope-intercept Form

A way of writing linear equations using the formula \(y = mx + b\), where \(m\) is the slope of the line and \(b\) is the y-intercept.

Slope

The calculation of how steep or inclined a line is, determined by the ratio of its vertical shift to its horizontal shift between any two points on the line.

  • Utilize the slope-intercept format to formulate the equation of a line.
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ZK
Zybrea KnightJun 07, 2024
Final Answer :
D
Explanation :
The slope-intercept form of a line is y=mx+by = mx + by=mx+b , where mmm is the slope and bbb is the y-intercept. Given the slope m=32m = \frac{3}{2}m=23 and the point (0,87)(0, \frac{8}{7})(0,78) , which represents the y-intercept ( bbb ), the equation is y=32x+87y = \frac{3}{2}x + \frac{8}{7}y=23x+78 .