Asked by Nyasia Green on Apr 29, 2024
Verified
Write 8x−6y+1=08 x - 6 y + 1 = 08x−6y+1=0 in slope-intercept form.
A) y=43x+16y = \frac { 4 } { 3 } x + \frac { 1 } { 6 }y=34x+61
B) y=34x+16y = \frac { 3 } { 4 } x + \frac { 1 } { 6 }y=43x+61
C) y=43x−16y = \frac { 4 } { 3 } x - \frac { 1 } { 6 }y=34x−61
D) y=−43x+16y = - \frac { 4 } { 3 } x + \frac { 1 } { 6 }y=−34x+61
E) y=43x+1y = \frac { 4 } { 3 } x + 1y=34x+1
Slope-Intercept Form
The equation of a straight line in the form y = mx + b, where m is the slope and b is the y-intercept.
Equation
A mathematical statement that asserts the equality of two expressions, symbolized by the equals sign.
- Modify equations to transition from the general form to the slope-intercept structure.
Verified Answer
DB
Diana BetancourthMay 01, 2024
Final Answer :
A
Explanation :
To convert 8x−6y+1=08x - 6y + 1 = 08x−6y+1=0 to slope-intercept form ( y=mx+by = mx + by=mx+b ), solve for yyy : 6y=8x+16y = 8x + 16y=8x+1 , then y=43x+16y = \frac{4}{3}x + \frac{1}{6}y=34x+61 .
Learning Objectives
- Modify equations to transition from the general form to the slope-intercept structure.