Asked by Monique Jimenez on May 09, 2024
Verified
Write an equation in slope-intercept form of the line that passes through the point (0,9) and has a slope of m=15m = \frac { 1 } { 5 }m=51 .
A) y=15x+9y = \frac { 1 } { 5 } x + 9y=51x+9
B) y=15x+59y = \frac { 1 } { 5 } x + \frac { 5 } { 9 }y=51x+95
C) y=15x−9y = \frac { 1 } { 5 } x - 9y=51x−9
D) y=15x+95y = \frac { 1 } { 5 } x + \frac { 9 } { 5 }y=51x+59
E) y=−15x+9y = - \frac { 1 } { 5 } x + 9y=−51x+9
Slope-Intercept Form
A way of writing the equation of a line as y = mx + b, where m is the slope and b is the y-intercept.
Slope
The measure of the steepness or incline of a line, calculated as the ratio of the vertical change to the horizontal change between two points on the line.
Point
A specific location in space defined by coordinates in a given dimension.
- Compute the linear formula given a slope and one point.
- Reformulate equations from general format to slope-intercept configuration.
Verified Answer
JJ
Jacole JonesMay 11, 2024
Final Answer :
A
Explanation :
The equation of a line can be written in slope-intercept form as:
y=mx+by = mx + by=mx+b
where $m$ is the slope and $b$ is the y-intercept.
We are given that the line passes through the point $(0,9)$, which means that the y-intercept is 9. We are also given that the slope is $m = \frac{1}{5}$. Therefore, the equation of the line is:
y=15x+9y = \frac{1}{5}x + 9y=51x+9
which is choice A.
y=mx+by = mx + by=mx+b
where $m$ is the slope and $b$ is the y-intercept.
We are given that the line passes through the point $(0,9)$, which means that the y-intercept is 9. We are also given that the slope is $m = \frac{1}{5}$. Therefore, the equation of the line is:
y=15x+9y = \frac{1}{5}x + 9y=51x+9
which is choice A.
Learning Objectives
- Compute the linear formula given a slope and one point.
- Reformulate equations from general format to slope-intercept configuration.