Write an equation of the line that passes through the points $(-1,1.6)$ and $(-3,-4.4)$ . Write the equation in general form.

A) $x-3y-4.6=0$
B) $3x+y+5.8=0$
C) $-3x+y+5.8=0$
D) $-3x+y-4.6=0$
E) $x+3y-4.6=0$

The equation can be found using the slope-intercept form, which is $y=mx+b$ where $m$ is the slope and $b$ is the y-intercept. First, we need to find the slope of the line using the two points:
$$m=\frac{y_2-y_1}{x_2-x_1}=\frac{-4.4-1.6}{-3-(-1)}=\frac{-6}{-2}=3$$
Now we can use the point-slope form of the equation, substituting one of our given points:
$$y-y_1=m(x-x_1)$$
$$y-1.6=3(x+1)$$
Simplifying, we get:
$$y=3x+4.4$$
To put it in general form, we can move the constant term to the other side:
$$-3x+y-4.4=0$$
Which matches choice D.