Asked by Garrett Spain on Jul 22, 2024

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Solve ∣a+8∣2≥20\frac { | a + 8 | } { 2 } \geq 202a+8∣20 , if possible. Write the answer in set notation.

A) {a∣a≤−48 or a≥32}\{ a \mid a \leq - 48 \text { or } a \geq 32 \}{aa48 or a32}
B) {a∣a≤−96 or a≥64}\{ a \mid a \leq - 96 \text { or } a \geq 64 \}{aa96 or a64}
C) {a∣−48≤a≤32}\{ a \mid - 48 \leq a \leq 32 \}{a48a32}
D) {a∣−96≤a≤64}\{ a \mid - 96 \leq a \leq 64 \}{a96a64}
E) no solution

Set Notation

A symbolic way of representing and specifying a set and its elements using curly brackets and specific symbols.

Absolute Value Inequality

An inequality that contains an absolute value expression, setting constraints on the range of solutions.

  • Learn to effectively solve inequalities associated with absolute values.
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Verified Answer

RK
Rubab Khalid

Jul 26, 2024

Final Answer :
A
Explanation :
To solve ∣a+8∣2≥20\frac { | a + 8 | } { 2 } \geq 202a+8∣20 , multiply both sides by 2 to get ∣a+8∣≥40| a + 8 | \geq 40a+8∣40 . This inequality means a+8≥40a + 8 \geq 40a+840 or a+8≤−40a + 8 \leq -40a+840 . Solving these gives a≥32a \geq 32a32 or a≤−48a \leq -48a48 , which matches option A.