Asked by Blake Churchill on Mar 10, 2024

verifed

Verified

Transform the absolute value inequality ∣2−2h∣≥7| 2 - 2 h | \geq 7∣22h7 into two separate inequalities.

A) 2−2h≤72 - 2 h \leq 722h7 or 2−2h≥−72 - 2 h \geq - 722h7
B) 2−2h≥72 - 2 h \geq 722h7 or 2−2h≥72 - 2 h \geq 722h7
C) 2−2h≥72 - 2 h \geq 722h7 or 2−2h≥−72 - 2 h \geq - 722h7
D) 2−2h≥−72 - 2 h \geq - 722h7 or 2−2h≤−72 - 2 h \leq - 722h7
E) 2−2h≥72 - 2 h \geq 722h7 or 2−2h≤−72 - 2 h \leq - 722h7

Separate Inequalities

Involves dealing with two or more inequalities independently or in relation to each other.

Absolute Value Inequality

An inequality involving absolute values, which constrains the distance of a variable from zero on the real number line within certain bounds.

  • Develop proficiency in solving absolute value inequalities.
verifed

Verified Answer

CT
corey tuckerMar 10, 2024
Final Answer :
E
Explanation :
To separate the absolute value inequality, we need to consider two cases, one where the expression inside the absolute value is positive and the other where it is negative.
When 2−2h2 - 2h22h is positive, we have:
2−2h≥72-2h\geq722h7
Solving this inequality, we get:
h≤−52h\leq- \frac{5}{2}h25
When 2−2h2 - 2h22h is negative, we have:
−(2−2h)≥7-(2-2h)\geq7(22h)7
Simplifying, we get:
2h−2≤−72h-2\leq-72h27
Solving this inequality, we get:
h≤−52h\leq-\frac{5}{2}h25
Thus, combining the two inequalities, we get:
h≤−52h\leq-\frac{5}{2}h25 or 2−2h≥72-2h\geq722h7 or 2−2h≤−72-2h\leq-722h7
The final inequality can be further simplified as:
h≥94h\geq\frac{9}{4}h49 or h≤−52h\leq-\frac{5}{2}h25