Asked by Murali Krishna on May 12, 2024
Verified
Each R requires 2 of component S and 1 of part T. The lead time for assembly of R is 3 days. The lead time for the manufacture of S is 5 days. The lead time for the manufacture of T is 10 days. The cumulative lead time for R is ________ days.
A) 6
B) 9
C) 13
D) 17
E) 22
Cumulative Lead Time
The sum of all lead times involved in the process of completing a product, from raw material acquisition to finished good.
Assembly
The process of putting together components or parts to form a finished product.
- Understand the principle of lead times and their effects on the planning of production and procurement processes.
Verified Answer
CG
Cristina GutierrezMay 17, 2024
Final Answer :
C
Explanation :
To manufacture one R, we need 2S and 1T.
The lead time for making S is 5 days, and we need 2S for one R, so the lead time for producing enough S for one R is 2*5 = 10 days.
The lead time for making T is 10 days, so the lead time for producing enough T for one R is 10 days.
Thus, the total lead time for producing one R is 10+10+3 = 23 days.
Therefore, the cumulative lead time for R is 13 days.
The lead time for making S is 5 days, and we need 2S for one R, so the lead time for producing enough S for one R is 2*5 = 10 days.
The lead time for making T is 10 days, so the lead time for producing enough T for one R is 10 days.
Thus, the total lead time for producing one R is 10+10+3 = 23 days.
Therefore, the cumulative lead time for R is 13 days.
Learning Objectives
- Understand the principle of lead times and their effects on the planning of production and procurement processes.