Use a short form truth table to answer the following question.Which, if any, set of truth values assigned to the atomic sentences shows that the following argument is invalid? $\begin{array} { l } ( \mathrm { J } \bullet \sim \mathrm { V } ) \supset ( \mathrm { R } \vee \mathrm { D } ) \\\sim \mathrm { R } \\\sim \mathrm { D } \\\sim ( \mathrm { J } \bullet \sim \mathrm { V } ) \end{array}$

A) J: T V: T R: T D: T
B) J: T V: T R: F D: F
C) J: F V: F R: T D: T
D) J: F V: F R: F D: F
E) None-the argument is valid.

Question

Use a short form truth table to answer the following question.Which, if any, set of truth values assigned to the atomic sentences shows that the following argument is invalid?

\begin{array} { l } ( \mathrm { J } \bullet \sim \mathrm { V } ) \supset ( \mathrm { R } \vee \mathrm { D } ) \\\sim \mathrm { R } \\\sim \mathrm { D } \\\sim ( \mathrm { J } \bullet \sim \mathrm { V } ) \end{array}

A) J: T V: T R: T D: T
B) J: T V: T R: F D: F
C) J: F V: F R: T D: T
D) J: F V: F R: F D: F
E) None-the argument is valid.

Monica Melendez · Accepted Answer

Final Answer : E, Explanation :   The argument is valid because there is no set of truth values that makes all the premises true and the conclusion false. The premises logically lead to the negation of   J ∙ ∼ V J \bullet \sim V J ∙ ∼ V  , making the argument valid.

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