Given the pK a values for the two acids below, what would you expect the K eq for this reaction to be? a values for the two acids below, what would you expect the K eq for this reaction to be? A) K eq 1 B) K eq = 1 C) K eq A) K eq 1B) K eq = 1C) K eq

Question

Given the pK a values for the two acids below, what would you expect the K eq for this reaction to be? a values for the two acids below, what would you expect the K eq for this reaction to be? A) K eq > 1 B) K eq = 1 C) K eq < 1 D) You can't tell from the information given. class=answers-bank-image d-block rel=preload >A) K eq > 1B) K eq = 1C) K eq < 1D) You can't tell from the information given.

Shahin Salimian · Accepted Answer

Final Answer : C, Explanation :  The equilibrium constant for the reaction of two acids is equal to the product of their dissociation constants. K eq  = [H3O+][A-]/[HA], and since the dissociation constants for both acids are greater than 1 (as indicated by the pK a  values), their product will be even greater than 1. Therefore, K eq  is greater than 1, and the correct answer is C.

Given the pK_a values for the two acids below, what would you expect the K_eq for this reaction to be?

A) K_eq> 1
B) K_eq= 1
C) K_eq< 1
D) You can't tell from the information given.

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Learning Objectives

Learning Objectives

Related questions

Given the pKa values for the two acids below, what would you expect the Keq for this reaction to be? A) Keq > 1B) Keq = 1C) Keq < 1D) You can't tell from the information given.

Definitions

Learning Objectives

Learning Objectives

Related questions

Given the pK_a values for the two acids below, what would you expect the K_eq for this reaction to be?

A) K_eq> 1
B) K_eq= 1
C) K_eq< 1
D) You can't tell from the information given.