In the reaction HA ⇌ H + + A - , what is the value of K if [HA] = 0.200 M and [A - ] = [H + ] = 0.020 M?A) 0.0004B) 0.200C) 0.010D) 0.002

Question

In the reaction HA ⇌ H +  + A - , what is the value of K if [HA] = 0.200 M and [A - ] = [H + ] = 0.020 M?A) 0.0004B) 0.200C) 0.010D) 0.002

Jacob Landry · Accepted Answer

Final Answer : D, Explanation :   The equilibrium constant   K K K   for the reaction   H A ⇌ H S + + A − HA \rightleftharpoons HS^+ + A^- H A ⇌ H S + + A −   is given by   K = [ H S + ] [ A − ] [ H A ] K = \frac{[HS^+][A^-]}{[HA]} K = [ H A ] [ H S + ] [ A − ] ​  . Substituting the given concentrations,   K = ( 0.020 ) ( 0.020 ) 0.200 = 0.0004 0.200 = 0.002 K = \frac{(0.020)(0.020)}{0.200} = \frac{0.0004}{0.200} = 0.002 K = 0.200 ( 0.020 ) ( 0.020 ) ​ = 0.200 0.0004 ​ = 0.002  .

In the reaction HA ⇌ H⁺ + A^-, what is the value of K if [HA] = 0.200 M and [A^-] = [H⁺] = 0.020 M?

A) 0.0004
B) 0.200
C) 0.010
D) 0.002

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Learning Objectives

Related questions

In the reaction HA ⇌ H+ + A-, what is the value of K if [HA] = 0.200 M and [A-] = [H+] = 0.020 M?A) 0.0004B) 0.200C) 0.010D) 0.002

Definitions

Learning Objectives

Learning Objectives

Related questions

In the reaction HA ⇌ H⁺ + A^-, what is the value of K if [HA] = 0.200 M and [A^-] = [H⁺] = 0.020 M?

A) 0.0004
B) 0.200
C) 0.010
D) 0.002