Asked by tanner fonoti on Apr 27, 2024

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Consider the reaction of A being converted into B at 25°C. If the ΔG° of this reaction is Consider the reaction of A being converted into B at 25°C. If the ΔG° of this reaction is   the K<sub>eq</sub> is ________ and the % conversion is ________. A)  0.18; 15% B)  0.43; 30% C)  1.0; 50% D)  2.3; 70% E)  5.4; 84% the Keq is ________ and the % conversion is ________.

A) 0.18; 15%
B) 0.43; 30%
C) 1.0; 50%
D) 2.3; 70%
E) 5.4; 84%

% Conversion

The percentage indicating how much of the reactants have been transformed into products in a chemical reaction.

ΔG°

The change in standard Gibbs free energy during a chemical reaction, indicating spontaneity at standard conditions.

  • Explain the function and importance of the equilibrium constant (Keq) within chemical reactions.
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EG
elise greenlandMay 01, 2024
Final Answer :
D
Explanation :
We can use the relationship between ΔG° and K to find the equilibrium constant for the reaction:

ΔG° = -RT lnK

Solving for K, we get:

K = e^(-ΔG°/RT)

Plugging in the given values, we get:

K = e^(-We can use the relationship between ΔG° and K to find the equilibrium constant for the reaction:  ΔG° = -RT lnK  Solving for K, we get:  K = e^(-ΔG°/RT)  Plugging in the given values, we get:  K = e^(- /(8.314 J/mol*K * 298 K)) = 2.3  Using the equilibrium constant and the stoichiometry of the reaction, we can find the percentage conversion of A to B:  K = [B]/[A] = (x/[A]0)/(1-x), where x is the fraction of A that has reacted and [A]0 is the initial concentration of A.  Solving for x, we get:  x = K[A]0/(1+K[A]0) = 0.7  Therefore, the % conversion is 70%, which is closest to answer choice D, 2.3; 70%./(8.314 J/mol*K * 298 K)) = 2.3

Using the equilibrium constant and the stoichiometry of the reaction, we can find the percentage conversion of A to B:

K = [B]/[A] = (x/[A]0)/(1-x), where x is the fraction of A that has reacted and [A]0 is the initial concentration of A.

Solving for x, we get:

x = K[A]0/(1+K[A]0) = 0.7

Therefore, the % conversion is 70%, which is closest to answer choice D, 2.3; 70%.