Find the height in feet of a free-falling object at time t=5 using the function $s=-16t^2+76t+118$ .

A) 138 feet
B) 98 feet
C) 20 feet
D) 662 feet
E) 898 feet

To find the height at time t=5, we need to substitute t=5 into the given function.

$s = - 16 t ^ { 2 } + 76 t + 118$

$s = - 16 (5)^2 + 76 (5) + 118$

$s = - 400 + 380 + 118$

$s = 98$

Therefore, the height of the free-falling object at time t=5 is 98 feet, which corresponds to choice B.