Asked by Naderay Atefi on May 17, 2024

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Find the height in feet of a free-falling object at time t=0 using the function s=−16t2+11t+30s = - 16 t ^ { 2 } + 11 t + 30s=16t2+11t+30 .

A) 30 feet
B) 32 feet
C) 22 feet
D) 60 feet
E) 16 feet

Free-Falling Object

An object that is only under the influence of gravity, with no other forces acting on it.

  • Utilize algebraic techniques to resolve practical problems related to movement and surface area.
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SD
Sofia Dela GarzaMay 19, 2024
Final Answer :
A
Explanation :
To find the height at t=0t=0t=0 , substitute t=0t=0t=0 into the function s=−16t2+11t+30s = -16t^2 + 11t + 30s=16t2+11t+30 , which gives s=−16(0)2+11(0)+30=30s = -16(0)^2 + 11(0) + 30 = 30s=16(0)2+11(0)+30=30 .