Asked by Punitha Nallusamy on May 12, 2024
Verified
Find the height in feet of a free-falling object at time t=2 using the function s=−16t2+57t+53s = - 16 t ^ { 2 } + 57 t + 53s=−16t2+57t+53 .
A) 125 feet
B) 231 feet
C) 50 feet
D) 3 feet
E) 103 feet
Free-Falling Object
An object that is under the influence of gravity only, with no other forces acting on it.
- Employ algebraic strategies to address real-life issues concerning displacement and area.
Verified Answer
MK
Mallory KatherineMay 14, 2024
Final Answer :
E
Explanation :
To find the height of a free-falling object at time t=2, we need to plug in t=2 into the given function and solve for s.
s=−16(2)2+57(2)+53=−64+114+53=103s=-16(2)^2+57(2)+53=-64+114+53=103s=−16(2)2+57(2)+53=−64+114+53=103
Therefore, the height of the object at time t=2 is 103 feet, so the best choice is E.
s=−16(2)2+57(2)+53=−64+114+53=103s=-16(2)^2+57(2)+53=-64+114+53=103s=−16(2)2+57(2)+53=−64+114+53=103
Therefore, the height of the object at time t=2 is 103 feet, so the best choice is E.
Learning Objectives
- Employ algebraic strategies to address real-life issues concerning displacement and area.