Use the Quadratic Formula to solve 4 x 2 − 12 x + 6 = 0 4 x ^ { 2 } - 12 x + 6 = 0 4 x 2 − 12 x + 6 = 0 , if possible. Round your answer(s) to two decimal places.A) x = 18.87 , x = 17.13 x = 18.87 , x = 17.13 x = 18.87 , x = 17.13 B) x = − 0.63 , x = − 2.37 x = - 0.63 , x = - 2.37 x = − 0.63 , x = − 2.37 C) x = 9.46 , x = 2.54 x = 9.46 , x = 2.54 x = 9.46 , x = 2.54 D) x = 2.37 , x = 0.63 x = 2.37 , x = 0.63 x = 2.37 , x = 0.63 E) no solutions

Question

Use the Quadratic Formula to solve   4 x 2 − 12 x + 6 = 0 4 x ^ { 2 } - 12 x + 6 = 0 4 x 2 − 12 x + 6 = 0   , if possible. Round your answer(s) to two decimal places.A)    x = 18.87 , x = 17.13 x = 18.87 , x = 17.13 x = 18.87 , x = 17.13 B)    x = − 0.63 , x = − 2.37 x = - 0.63 , x = - 2.37 x = − 0.63 , x = − 2.37 C)    x = 9.46 , x = 2.54 x = 9.46 , x = 2.54 x = 9.46 , x = 2.54 D)    x = 2.37 , x = 0.63 x = 2.37 , x = 0.63 x = 2.37 , x = 0.63 E) no solutions

Queshante Clark · Accepted Answer

Final Answer : D, Explanation :   The quadratic formula is   x = − b ± b 2 − 4 a c 2 a x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} x = 2 a − b ± b 2 − 4 a c ​ ​  , where   a = 4 a = 4 a = 4  ,   b = − 12 b = -12 b = − 12  , and   c = 6 c = 6 c = 6  . Plugging these values in gives   x = 12 ± ( − 12 ) 2 − 4 ( 4 ) ( 6 ) 2 ( 4 ) = 12 ± 144 − 96 8 = 12 ± 48 8 = 12 ± 6.93 8 x = \frac{12 \pm \sqrt{(-12)^2 - 4(4)(6)}}{2(4)} = \frac{12 \pm \sqrt{144 - 96}}{8} = \frac{12 \pm \sqrt{48}}{8} = \frac{12 \pm 6.93}{8} x = 2 ( 4 ) 12 ± ( − 12 ) 2 − 4 ( 4 ) ( 6 ) ​ ​ = 8 12 ± 144 − 96 ​ ​ = 8 12 ± 48 ​ ​ = 8 12 ± 6.93 ​  , which simplifies to   x = 2.37 x = 2.37 x = 2.37   and   x = 0.63 x = 0.63 x = 0.63  .

Use the Quadratic Formula to solve $4 x ^ { 2 } - 12 x + 6 = 0$ , if possible. Round your answer(s) to two decimal places.

A) $x = 18.87, x = 17.13$
B) $x = - 0.63, x = - 2.37$
C) $x = 9.46, x = 2.54$
D) $x = 2.37, x = 0.63$
E) no solutions

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