Use a short form truth table to answer the following question.Which, if any, set of truth values assigned to the atomic sentences shows that the following argument is invalid? $∼E\begin{array} { l } ( \mathrm { E }\cdot \sim \mathrm { H } ) \supset \mathrm { G } \\\sim ( \mathrm { H } \vee \mathrm { G } ) \\\sim \mathrm { E }\end{array}$

A) E: T H: T G: T
B) E: T H: T G: F
C) E: T H: F G: T
D) E: F H: F G: F
E) None-the argument is valid.

Question

Use a short form truth table to answer the following question.Which, if any, set of truth values assigned to the atomic sentences shows that the following argument is invalid?

∼E\begin{array} { l } ( \mathrm { E }\cdot \sim \mathrm { H } ) \supset \mathrm { G } \\\sim ( \mathrm { H } \vee \mathrm { G } ) \\\sim \mathrm { E }\end{array}

A) E: T H: T G: T
B) E: T H: T G: F
C) E: T H: F G: T
D) E: F H: F G: F
E) None-the argument is valid.

Abdel Taylor · Accepted Answer

Final Answer : E, Explanation :  The argument is valid because there is no set of truth values for E, H, and G that makes all the premises true and the conclusion false. In a valid argument, it is impossible to have all true premises and a false conclusion.

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