Asked by Olivia Anne Samonte on May 09, 2024

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The first unit of a product took 832 hours to build, and the learning curve is 75%. How long will it take to make the 30th unit? (Use at least three decimals in the exponent if you use the logarithmic approach.)

A) less than 200 hours
B) from 200 to 225 hours
C) from 225 to 250 hours
D) from 2501 to 275 hours
E) 275 or more hours

Logarithmic Approach

A mathematical method utilizing logarithms to solve problems or equations, often applied in growth models, decay processes, and complex calculations.

  • Formulate precise outcomes pertaining to production time and costs by leveraging the learning curve formula and logarithmic methods.
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Verified Answer

MY
Mustafa YilmazMay 14, 2024
Final Answer :
B
Explanation :
The time to produce the nth unit in a learning curve is given by Tn=T1×nlog⁡b(a)T_n = T_1 \times n^{\log_b(a)}Tn=T1×nlogb(a) , where T1T_1T1 is the time to produce the first unit, aaa is the learning percentage (as a decimal), and bbb is the base of the learning curve (usually 2 for a 75% learning curve, indicating a 25% reduction in time per doubling of output). Here, T1=832T_1 = 832T1=832 hours, a=0.75a = 0.75a=0.75 , and n=30n = 30n=30 . The exponent is log⁡2(0.75)\log_2(0.75)log2(0.75) , which is negative because 0.75<10.75 < 10.75<1 . To find the time to produce the 30th unit, we calculate: T30=832×30log⁡2(0.75)T_{30} = 832 \times 30^{\log_2(0.75)}T30=832×30log2(0.75) First, find the exponent: log⁡2(0.75)≈−0.415\log_2(0.75) \approx -0.415log2(0.75)0.415 Then, calculate the time for the 30th unit: T30=832×30−0.415≈832×0.234≈194.688T_{30} = 832 \times 30^{-0.415} \approx 832 \times 0.234 \approx 194.688T30=832×300.415832×0.234194.688 Thus, it will take just under 200 hours to produce the 30th unit, which falls into the range of "from 200 to 225 hours."