Asked by mykeria adkins on Jun 25, 2024
Verified
Ten high-technology batteries are tested for 200 hours each. One failed at 50 hours; all others completed the test. FR(%) is ________ and FR(N) is ________.
A) 10%; 1/1850
B) 10%; 1/2000
C) 25%; 1850 hours
D) 90%; 1/2000
E) Indeterminate; no standard deviation is given.
High-Technology Batteries
Batteries that utilize advanced technologies for better performance, longevity, and energy density compared to traditional battery types.
- Determine the mean interval between failures (MTBF) and calculate the frequency of failures (FR) with the specified information.
Verified Answer
FJ
Fatma JankabirJul 01, 2024
Final Answer :
A
Explanation :
- FR(%) = [(number of failed batteries) / (total number of batteries tested)] x 100%
- FR(N) = 1 / (total number of hours all batteries were tested)
- In this case, only one battery failed at 50 hours out of 200 hours it was tested, so FR(%) = (1/10) x 100% = 10%.
- FR(N) = 1 / (10 x 200) = 1/2000.
- Thus, the correct answer is A.
- FR(N) = 1 / (total number of hours all batteries were tested)
- In this case, only one battery failed at 50 hours out of 200 hours it was tested, so FR(%) = (1/10) x 100% = 10%.
- FR(N) = 1 / (10 x 200) = 1/2000.
- Thus, the correct answer is A.
Learning Objectives
- Determine the mean interval between failures (MTBF) and calculate the frequency of failures (FR) with the specified information.