Ten high-technology batteries are tested for 200 hours each. One failed at 20 hours; another failed at 140 hours; all others completed the test. FR(%) is and MTBF is .

A) 20%; 880 hours
B) 10%; 1980 hours
C) 20%; 1760 hours
D) cannot calculate from information provided
E) 80%; 920 hours

Question

Ten high-technology batteries are tested for 200 hours each. One failed at 20 hours; another failed at 140 hours; all others completed the test. FR(%) is ________ and MTBF is ________.

A) 20%; 880 hours
B) 10%; 1980 hours
C) 20%; 1760 hours
D) cannot calculate from information provided
E) 80%; 920 hours

miesha white · Accepted Answer

Final Answer : A, Explanation :  FR(%) = (Number of failed batteries / Total number of batteries) * 100 = (2 / 10) * 100 = 20%. MTBF = Total operational time / Number of failures = (200*8 + 20 + 140) / 2 = 1760 / 2 = 880 hours.

Ten high-technology batteries are tested for 200 hours each. One failed at 20 hours; another failed at 140 hours; all others completed the test. FR(%) is and MTBF is .

A) 20%; 880 hours
B) 10%; 1980 hours
C) 20%; 1760 hours
D) cannot calculate from information provided
E) 80%; 920 hours

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Learning Objectives

Related questions

Ten high-technology batteries are tested for 200 hours each. One failed at 20 hours; another failed at 140 hours; all others completed the test. FR(%) is ________ and MTBF is ________.A) 20%; 880 hoursB) 10%; 1980 hoursC) 20%; 1760 hoursD) cannot calculate from information providedE) 80%; 920 hours

Definitions

Learning Objectives

Learning Objectives

Related questions

Ten high-technology batteries are tested for 200 hours each. One failed at 20 hours; another failed at 140 hours; all others completed the test. FR(%) is and MTBF is .

A) 20%; 880 hours
B) 10%; 1980 hours
C) 20%; 1760 hours
D) cannot calculate from information provided
E) 80%; 920 hours