In a goodness-of-fit test,the null hypothesis states that the data came from a normally distributed population.The researcher estimated the population mean and population standard deviation from a sample of 300 observations.In addition,the researcher used 6 standardized intervals to test for normality.Using a 2.5% level of significance,the critical value for this test is 14.4494.

In a goodness-of-fit test, the critical value is determined by the degrees of freedom and the level of significance. The degrees of freedom for this test would be the number of intervals minus one minus the number of estimated parameters. Since two parameters (mean and standard deviation) were estimated from the sample, the degrees of freedom would be 6 - 1 - 2 = 3. The critical value for a chi-square distribution with 3 degrees of freedom at a 2.5% level of significance does not match the provided value of 14.4494.