Asked by Arteria Jones on May 29, 2024
Verified
If p = 0.8, what is the frequency of heterozygotes in a population, assuming Hardy-Weinberg equilibrium?
A) 0.2
B) 0.64
C) 0.16
D) 0.32
E) none of the above
Hardy-Weinberg Equilibrium
A principle that states the genetic variation in a population will remain constant from one generation to another in the absence of disturbing factors.
Heterozygotes
Individuals having two different alleles of a particular gene, resulting in a mixture of genetic traits.
- Acquire knowledge of the Hardy-Weinberg equilibrium and its underlying premises.
- Outline the correlation between frequencies of alleles and genotype frequencies in demographic populations.
Verified Answer
OV
Oshima VermaJun 01, 2024
Final Answer :
D
Explanation :
In a population at Hardy-Weinberg equilibrium, the frequency of heterozygotes can be calculated using the formula 2pq, where p is the frequency of one allele, and q is the frequency of the other allele. Given p = 0.8, q = 1 - p = 0.2. Therefore, the frequency of heterozygotes = 2(0.8)(0.2) = 0.32.
Learning Objectives
- Acquire knowledge of the Hardy-Weinberg equilibrium and its underlying premises.
- Outline the correlation between frequencies of alleles and genotype frequencies in demographic populations.