Asked by Kayla Valdes on May 02, 2024

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Calculate the lower and upper limits of the 90% confidence interval for a sample of N = 29 with a mean Calculate the lower and upper limits of the 90% confidence interval for a sample of N = 29 with a mean   = 137.98 and standard error of the mean   = 4.98. A)  (129.51, 146.45)  B)  (124.22, 151.74)  C)  (131.30, 144.66)  D)  (127.78, 148.18) = 137.98 and standard error of the mean Calculate the lower and upper limits of the 90% confidence interval for a sample of N = 29 with a mean   = 137.98 and standard error of the mean   = 4.98. A)  (129.51, 146.45)  B)  (124.22, 151.74)  C)  (131.30, 144.66)  D)  (127.78, 148.18) = 4.98.

A) (129.51, 146.45)
B) (124.22, 151.74)
C) (131.30, 144.66)
D) (127.78, 148.18)

Confidence Interval

A range of values, derived from sample statistics, that likely contains the true value of an unknown population parameter.

Standard Error

The standard deviation of the sample distribution of a statistic, often used in the context of mean.

Mean

The central or typical value in a distribution, calculated as the sum of all observations divided by the number of observations.

  • Ascertain precise confidence intervals from sample statistics.
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JB
Julie BemuyalMay 08, 2024
Final Answer :
A
Explanation :
To calculate the lower and upper limits of the 90% confidence interval, we use the formula:
CI = X̄ ± (Zα/2 x SE)
Where X̄ is the sample mean, SE is the standard error of the mean, and Zα/2 is the critical value of the standard normal distribution for the given confidence level (90% in this case).
Substituting the given values, we get:
CI = 137.98 ± (1.645 x 4.98)
Calculating the values, we get:
CI = (129.51, 146.45)
Therefore, the best choice is A.