Asked by Rodrigo Navarrete on May 27, 2024
Verified
Calculate the 99% confidence interval for a sample of N = 24 with a mean 
= 96.55 and standard deviation (s) = 7.54.
A) 99% CI = 96.55 ± 3.19
B) 99% CI = 96.55 ± 2.64
C) 99% CI = 96.55 ± 4.32
D) 99% CI = 96.55 ± 4.55
Confidence Interval
A selection of values, based on sample results, assumed to incorporate the value of an obscure population parameter.
Mean
The average value of a data set, calculated by adding up all the numbers in the set and then dividing by the count of the numbers.
- Estimate exact confidence intervals with the aid of sample statistics.
Verified Answer
YG
Yanelly GuzmanMay 28, 2024
Final Answer :
C
Explanation :
To calculate the 99% confidence interval, we use the formula:
99% CI = X̄ ± (t_critical)*(s/√n)
where X̄ is sample mean, s is sample standard deviation, n is sample size, and t_critical is the t-score from the t-distribution table with (n-1) degrees of freedom and 99% confidence level.
Plugging in the values, we get:
99% CI = 96.55 ± (2.797)*(7.54/√24)
99% CI = 96.55 ± 4.32
Therefore, the answer is C.
99% CI = X̄ ± (t_critical)*(s/√n)
where X̄ is sample mean, s is sample standard deviation, n is sample size, and t_critical is the t-score from the t-distribution table with (n-1) degrees of freedom and 99% confidence level.
Plugging in the values, we get:
99% CI = 96.55 ± (2.797)*(7.54/√24)
99% CI = 96.55 ± 4.32
Therefore, the answer is C.
Learning Objectives
- Estimate exact confidence intervals with the aid of sample statistics.
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