Which H atom in the molecule shown will be most readily abstracted by a bromine radical? a B) H b C) H c D) H d E) H e class=answers-bank-image d-block rel=preload A) H a B) H b C) H c D) H d E) H e

Question

Which H atom in the molecule shown will be most readily abstracted by a bromine radical?  a  B)  H b  C)  H c  D)  H d  E)  H e  class=answers-bank-image d-block rel=preload >A)  H a B)  H b C)  H c D)  H d E)  H e

Sairyl Navasca · Accepted Answer

Final Answer : C, Explanation :  The H atom on the carboxyl group (H c ) will be most readily abstracted by a bromine radical because it is the most weakly bonded to the molecule due to the electron-withdrawing effect of the nearby carbonyl group. This weakens the bond between the H atom and the neighboring O atom, making it more susceptible to abstraction by a radical.

Which H atom in the molecule shown will be most readily abstracted by a bromine radical?

A) H_a
B) H_b
C) H_c
D) H_d
E) H_e

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Learning Objectives

Learning Objectives

Related questions

Which H atom in the molecule shown will be most readily abstracted by a bromine radical? A) HaB) HbC) HcD) HdE) He

Definitions

Learning Objectives

Learning Objectives

Related questions

Which H atom in the molecule shown will be most readily abstracted by a bromine radical?

A) H_a
B) H_b
C) H_c
D) H_d
E) H_e