Asked by Kimberly Zayas-Maciel on May 19, 2024

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Use a special product formula to find the product. (0.1x+0.4) (0.1x−0.4) ( 0.1 x + 0.4 ) ( 0.1 x - 0.4 ) (0.1x+0.4) (0.1x0.4)

A) 0.01x2−0.160.01 x ^ { 2 } - 0.160.01x20.16
B) 0.01x2−0.08x+0.160.01 x ^ { 2 } - 0.08 x + 0.160.01x20.08x+0.16
C) 0.01x2+0.160.01 x ^ { 2 } + 0.160.01x2+0.16
D) 0.01x2+0.08x−0.160.01 x ^ { 2 } + 0.08 x - 0.160.01x2+0.08x0.16
E) 0.01x2−0.04x+0.160.01 x ^ { 2 } - 0.04 x + 0.160.01x20.04x+0.16

Special Product Formula

Mathematical formulas that provide shortcuts for multiplying certain types of polynomials.

  • Utilize unique product patterns to expedite the simplification of expressions with polynomials.
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Verified Answer

AS
Anissa SantellanoMay 20, 2024
Final Answer :
A
Explanation :
Using the special product formula (a+b)(a−b)=a2−b2(a+b)(a-b)=a^2-b^2(a+b)(ab)=a2b2 , we have
(0.1x+0.4)(0.1x−0.4)=(0.1x)2−(0.4)2=0.01x2−0.16\begin{align*}(0.1x+0.4)(0.1x-0.4)&=(0.1x)^2-(0.4)^2\\&=0.01x^2-0.16\end{align*}(0.1x+0.4)(0.1x0.4)=(0.1x)2(0.4)2=0.01x20.16
Thus, the correct choice is A.