Asked by Lauren Cantrell on Jun 19, 2024
Verified
Treatment of a monosaccharide with silver oxide and excess methyl iodide will ________.
A) methylate all hydroxyl groups present
B) cleave the sugar between C5 and C6
C) cleave the sugar between C1 and C6
D) methylate only the hydroxyl at C1
E) form the disaccharide
Silver Oxide
A chemical compound of silver and oxygen that's used in some batteries and as a mild oxidizing agent in organic synthesis.
Methyl Iodide
A chemical compound with the formula CH3I, used as a methylating agent in organic synthesis.
- Learn about the chemical modifications and reactions of monosaccharides (e.g., methylation, oxidation) and their outcomes.
Verified Answer
KG
KENDELL GRACEJun 19, 2024
Final Answer :
A
Explanation :
Treatment of a monosaccharide with silver oxide and excess methyl iodide is a method used to methylate all hydroxyl groups present in the sugar molecule. This reaction is known as the Hakomori methylation.
Learning Objectives
- Learn about the chemical modifications and reactions of monosaccharides (e.g., methylation, oxidation) and their outcomes.
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