The two-way table summarizes data from the human resource department at a university: New Hires $374683\begin{array} { l | c c | c } & \text { Tenure } & \text { Adjunct } & \text { Total } \\\hline \text { Men } & 17 & 25 & 42 \\\text { Women } & 20 & 21 & 41 \\\hline \text { Total } & 37 & 46 & 83\end{array}$ What is the probability (rounded to two decimal places) of a randomly selected new hire being tenure track given that the new hire is a woman?

A) 0
B) 0.51
C) 0.49
D) 0.20
E) 0.24

Question

The two-way table summarizes data from the human resource department at a university: New Hires

374683\begin{array} { l | c c | c } & \text { Tenure } & \text { Adjunct } & \text { Total } \\\hline \text { Men } & 17 & 25 & 42 \\\text { Women } & 20 & 21 & 41 \\\hline \text { Total } & 37 & 46 & 83\end{array}

What is the probability (rounded to two decimal places) of a randomly selected new hire being tenure track given that the new hire is a woman?

A) 0
B) 0.51
C) 0.49
D) 0.20
E) 0.24

Devon Atkinson · Accepted Answer

Final Answer : C, Explanation :  To find the probability of a randomly selected new hire being tenure track given that they are a woman, we need to look at the female row in the table. Out of the 40 new female hires, 20 are tenure track. So the probability is 20/40 = 0.5 or 50%. Rounded to two decimal places, this is 0.49, which is closest to answer choice C.

Definitions

Learning Objectives

Learning Objectives

Related questions