The life expectancy of a particular brand of tire is normally distributed with a mean of 40,000 and a standard deviation of 5,000 miles.What is the probability that a randomly selected tire will have a life of at least 52,500 miles?

A) 0.0062
B) 0.9938
C) 0.0000
D) 1.0000

To find the probability that a randomly selected tire will have a life of at least 52,500 miles, we use the Z-score formula: Z = (X - μ) / σ, where X is the value of interest (52,500 miles), μ is the mean (40,000 miles), and σ is the standard deviation (5,000 miles). Plugging in the values, we get Z = (52,500 - 40,000) / 5,000 = 2.5. Looking up the Z-score of 2.5 in a standard normal distribution table or using a calculator, we find that the area to the right of Z = 2.5 (which represents the probability of a tire lasting at least 52,500 miles) is approximately 0.0062.