Asked by Jennie McLean on Apr 26, 2024

verifed

Verified

The following ANOVA table shows the results of an experiment used to test how race car drivers and different tracks affect time.The experiment used 3 different drivers on 4 different tracks.Assuming no effect from the interaction between driver and track,test the claim that the three drivers have the same mean time.  Sum ofMean Source  DF  Squares  Square  F-ratio  P-value  Driver 2210.330.729 Tradk 398.2532.7510.92<0.0001 Error 6183 Total 11118.25\begin{array}{l}\begin{array} { l r c c c c } &&\text { Sum of}&{ Mean }\\\text { Source } & \text { DF } & \text { Squares } & \text { Square } & \text { F-ratio } & \text { P-value } \\\text { Driver } & 2 & 2 & 1 & 0.33 & 0.729 \\\text { Tradk } & 3 & 98.25 & 32.75 & 10.92 & < 0.0001 \\\text { Error } & 6 & 18 & 3 & & \\\text { Total } & 11 & 118.25 & & &\end{array}\end{array} Source  Driver  Tradk  Error  Total  DF 23611 Sum of Squares 298.2518118.25Mean Square 132.753 F-ratio 0.3310.92 P-value 0.729<0.0001

ANOVA Table

A table used to summarize the data analysis for an Analysis of Variance, showing sources of variance, degrees of freedom, sum of squares, mean squares, and the F-statistic.

F-ratio

A statistical measure used in ANOVA testing that compares the variances between groups to variances within groups.

P-value

A statistic that measures the probability of obtaining test results at least as extreme as the results actually observed, assuming that the null hypothesis is correct.

  • Evaluate ANOVA (Analysis of Variance) tables to determine the significance of mean differences between groups.
  • Evaluate the results of ANOVA tests, paying particular attention to the F-ratio and p-value, to determine statistical actions.
  • Understand the implications of statistical findings for practical applications and decision-making.
verifed

Verified Answer

KP
Kristen PeterkaMay 01, 2024
Final Answer :
H0: γ1 = γ2 = γ3,where γ represents the effect of the driver vs.HA: Not all of the drivers have the same effect.The null hypothesis states that the driver has no effect on the time.The alternative states that it does.The P-value for the driver is 0.729,providing insufficient evidence that the driver has an effect on mean times.