Asked by Hoala Chock on Jun 30, 2024

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Suppose the following random numbers (1, 34, 22, 78, 56, 98, 00, 82) were selected during a Monte Carlo simulation that was based on the chart below. What was the average demand per period for the simulation? What is the expected demand?
 Demand  Probability  Cumulative  Probability  Interval of Random  Numbers 0.11.152.43.154.2\begin{array} { | c | c | c | c | } \hline \text { Demand } & \text { Probability } & \begin{array} { c } \text { Cumulative } \\\text { Probability }\end{array} & \begin{array} { c } \text { Interval of Random } \\\text { Numbers }\end{array} \\\hline 0 & .1 & & \\\hline 1 & .15 & & \\\hline 2 & .4 & & \\\hline 3 & .15 & & \\\hline 4 & .2 & & \\\hline\end{array} Demand 01234 Probability .1.15.4.15.2 Cumulative  Probability  Interval of Random  Numbers 

Cumulative Probability

The probability that a variable takes on a value less than or equal to a specific value.

Interval of Random Numbers

A range within which any number has an equal chance of being selected during a random selection process.

Average Demand

The mean amount of a product or service consumed or requested by customers over a specific period.

  • Obtain the ability to formulate probability distributions, cumulative distributions, and random number intervals.
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Black ShadowJul 01, 2024
Final Answer :
 Demand  Probability  Cumulative  Probability  Interval of Random  Numbers 0.1.101−101.15.2511−252.4.6526−653.15.866−804.2181−00\begin{array} { | c | c | c | c | } \hline \text { Demand } & \text { Probability } & \begin{array} { c } \text { Cumulative } \\\text { Probability }\end{array} & \begin{array} { c } \text { Interval of Random } \\\text { Numbers }\end{array} \\\hline 0 & .1 & .1 & 01 - 10 \\\hline 1 & .15 & .25 & 11 - 25 \\\hline 2 & .4 & .65 & 26 - 65 \\\hline 3 & .15 & .8 & 66 - 80 \\\hline 4 & .2 & 1 & 81 - 00 \\\hline\end{array} Demand 01234 Probability .1.15.4.15.2 Cumulative  Probability .1.25.65.81 Interval of Random  Numbers 01101125266566808100 Tires sold sum is given by 0 + 2 + 1 + 3 + 2 + 4 + 4 + 4 = 20 over 8 periods. Thus the average demand was 20/8 = 2.5 tires.
The expected demand is simply the EV, or .1(0) + .15(1) + .4(2) + .15(3) + .2(4) = 2.2 tires per period.