Solve the exponential equation. Round your answer to two decimal places. $7^{x+4}=26$

A) x=-2.59
B) x=-2.33
C) x=-0.74
D) x=-3.40
E) x=4.60

Taking the logarithm of both sides with base 7 we get:
\begin{aligned} \log_7{(7^{x+4})} &= \log_7{26} \\ x+4 &= \log_7{26} \\ x &= \log_7{26}-4 \\ x &\approx -2.33 \end{aligned}
Therefore the answer is B, which is the only choice rounded to two decimal places.