Asked by Jenna Garland on May 25, 2024

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Perform the division. 6z3+7z2−2z2z\frac { 6 z ^ { 3 } + 7 z ^ { 2 } - 2 z } { 2 z }2z6z3+7z22z

A) 3z2+7z2−1,z≠03 z ^ { 2 } + \frac { 7 z } { 2 } - 1 , z \neq 03z2+27z1,z=0
B) 6z3+7z2,z≠06 z ^ { 3 } + 7 z ^ { 2 } , z \neq 06z3+7z2,z=0
C) 13z22−2z,z≠0\frac { 13 z ^ { 2 } } { 2 } - 2 z , z \neq 0213z22z,z=0
D) 6z3+5z2,z≠06 z ^ { 3 } + \frac { 5 z } { 2 } , z \neq 06z3+25z,z=0
E) 10z2−2z,z≠010 z ^ { 2 } - 2 z , z \neq 010z22z,z=0

Division

A mathematical operation in which a number, the dividend, is divided by another number, the divisor, to produce a quotient.

Simplify

To reduce a mathematical expression or equation to its simplest form without changing its value.

  • Condense variables and exponents in expressions to a more simplified state.
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Verified Answer

LP
Laxmi PrasannaMay 28, 2024
Final Answer :
A
Explanation :
Dividing each term in the numerator by 2z2z2z gives 3z2+7z2−13z^2 + \frac{7z}{2} - 13z2+27z1 , with the condition z≠0z \neq 0z=0 to avoid division by zero.