In a completely randomized experimental design involving five treatments, 13 observations were recorded for each of the five treatments (a total of 65 observations) .The following information is provided. ​
SSTR = 300 (Sum of Squares Due to Treatments)
SST = 800 (Total Sum of Squares)
​
The test statistic is

A) .11.
B) 9.04.
C) 3.75.
D) 15.

We can use the F-test to test the null hypothesis that there is no difference among the means of the five treatments. The test statistic is given by:

F = (SSTR / k-1) / (SSE / n-k)

where k is the number of treatments and n is the total number of observations.

Using the given information, we have:

k = 5
n = 65
SSTR = 300
SSE = SST - SSTR = 800 - 300 = 500

Plugging in these values, we get:

F = (300 / 4) / (500 / 60) = 9.04

Looking up the F-distribution with 4 and 60 degrees of freedom (numerator and denominator, respectively), we find the p-value to be very small (less than 0.01). Therefore, we can reject the null hypothesis and conclude that there is a significant difference among the means of the five treatments.