Asked by LaNeigh Jones on Jul 19, 2024

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import java.util.*;
Public class ExceptionExample1
{
Static Scanner console = new Scanner(System.in) ; public static void main(String[] args)
{
Int dividend, divisor, quotient; try
{
System.out.print("Enter dividend: ") ;
Dividend = console.nextInt() ;
System.out.println() ;
System.out.print("Enter divisor: ") ;
Divisor = console.nextInt() ;
System.out.println() ;
Quotient = dividend / divisor;
System.out.println("quotient = " + quotient) ;
}
Catch (ArithmeticException aeRef)
{
System.out.println("Exception" + aeRef.toString() ) ;
}
Catch (InputMismatchException imeRef)
{
System.out.println("Exception "
+ imeRef.toString() ) ;
}
Catch( IOException ioeRef)
{
System.out.println("Exception "
+ ioeRef.toString() ) ;
}
}
}Which of the following will cause the first exception to occur in the code in the accompanying figure?

A) If the divisor is zero
B) If the dividend is zero
C) If the quotient is zero
D) This code will not compile, so an exception cannot be triggered.

ArithmeticException

A type of exception in Java that occurs when an illegal arithmetic operation is performed, like division by zero.

Divisor Zero

Refers to the attempt of dividing a number by zero, which is undefined and causes an error in many programming environments.

  • Gain insight into the role of exceptions in Java and how they affect program operation.
  • Gain insight into the mechanisms of defining and employing exceptions to dictate program progression.
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Verified Answer

MT
Monica TerryJul 19, 2024
Final Answer :
A
Explanation :
The first exception that may occur in the code is an ArithmeticException, which is triggered when the divisor is zero, causing a division by zero error. The other exceptions listed (InputMismatchException and IOException) are not relevant to the code in the given figure.