Asked by hafiz iskandarani on Jul 23, 2024

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If the total pressure of a mixture of gases was 760 mm Hg and its composition is 20% oxygen, 0.04% carbon dioxide, 75% nitrogen, and 5% water vapor, then the partial pressure of oxygen would be ________.

A) 740 mm Hg
B) 20 mm Hg
C) 148 mm Hg
D) 152 mm Hg
E) 200 mm Hg

Partial Pressure

Pressure exerted by a single gas in a mixture of gases.

Mixture of Gases

A combination of different gases, where each gas retains its own chemical identity and properties.

  • Explain the concept of partial pressures and their calculation for gases in a mixture.
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NQ
Nguyen Quoc Viet (K15 HL)Jul 24, 2024
Final Answer :
D
Explanation :
The partial pressure of oxygen can be calculated by multiplying the total pressure by the percentage of oxygen in the mixture: 760 mm Hg×0.20=152 mm Hg760 \, \text{mm Hg} \times 0.20 = 152 \, \text{mm Hg}760mm Hg×0.20=152mm Hg .