If output is produced according to Q  4L  6K, the price of K is $12, and the price of L is $20, then the cost-minimizing combination of K and L capable of producing 96 units of output is

A) L  20 and K  12.
B) L  0 and K  16.
C) L  24 and K  16.
D) L  12 and K  8.
E) L  24 and K  0.

Given the output formula and the prices of K and L, the most cost-effective strategy to produce 96 units of output involves using only K, as it has a lower cost per unit of output compared to L. This eliminates the need for L, leading to the selection of option B, which specifies using 16 units of K and 0 units of L to achieve the desired output.