Asked by Akash singhania on May 27, 2024
Verified
If a gas at 15 atm occupying 5.0 L at 25°C is pressurized to 25 atm at 10 L, what will the new temperature of the gas be?
A) 0.012°C
B) 83.3°C
C) 3.0°C
D) 75.0°C
Atm
A unit of pressure defined as being equal to the atmospheric pressure at sea level, approximately 101.325 kPa or 760 mmHg.
Temperature
A measure of the average kinetic energy of the particles in a system, indicating how hot or cold the system is.
°C
A scale and unit of measurement for temperature where 0°C is the freezing point of water and 100°C is its boiling point at 1 atmosphere of pressure.
- Implement the combined gas law to tackle problems related to the adjustments in pressure, volume, and temperature of gases.
- Define the connection between temperature, pressure, volume, and mole numbers in gases according to the ideal gas law.
Verified Answer
DK
Dachi KvirikadzeJun 02, 2024
Final Answer :
B
Explanation :
To find the new temperature of the gas, we can use the combined gas law, which is P1V1/T1=P2V2/T2P_1V_1/T_1 = P_2V_2/T_2P1V1/T1=P2V2/T2 , where PPP is pressure, VVV is volume, and TTT is temperature in Kelvin. First, convert the initial temperature to Kelvin: 25°C+273=298K25°C + 273 = 298K25°C+273=298K . Then, rearrange the formula to solve for T2T_2T2 : T2=(P2V2T1)/(P1V1)T_2 = (P_2V_2T_1)/(P_1V_1)T2=(P2V2T1)/(P1V1) . Plugging in the values gives T2=(25×10×298)/(15×5)=2980KT_2 = (25 \times 10 \times 298) / (15 \times 5) = 2980KT2=(25×10×298)/(15×5)=2980K . Converting back to Celsius: 2980K−273=83.3°C2980K - 273 = 83.3°C2980K−273=83.3°C .
Learning Objectives
- Implement the combined gas law to tackle problems related to the adjustments in pressure, volume, and temperature of gases.
- Define the connection between temperature, pressure, volume, and mole numbers in gases according to the ideal gas law.