Asked by Matthew Torres on Jun 20, 2024

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If 78.0 g of potassium are consumed to make KCl according to the equation 2 K + Cl2 → 2 KCl, how much product can form?

A) 149 g
B) 0.023 g
C) 40.8 g
D) 78.0 g

Potassium

A soft, silvery-white metallic element, very reactive, especially in water, and essential for plant and animal life.

KCl

KCl, known as potassium chloride, is a metal halide salt composed of potassium and chlorine, used in medicine, food processing, and as a fertilizer.

Moles

A unit of measure in chemistry that represents 6.022 x 10^23 particles of a substance.

  • Gain insight into the use of stoichiometric relationships for quantifying reactants and products in balanced chemical equations.
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Daniel McColloughJun 26, 2024
Final Answer :
A
Explanation :
The reaction 2 K + Cl2 → 2 KCl shows that 2 moles of potassium react with 1 mole of chlorine to produce 2 moles of KCl. The molar mass of potassium (K) is approximately 39.1 g/mol, so 78.0 g of potassium is about 2 moles (78.0 g / 39.1 g/mol). According to the stoichiometry of the reaction, these 2 moles of potassium will produce 2 moles of KCl. The molar mass of KCl is approximately 74.55 g/mol (39.1 g/mol for K + 35.45 g/mol for Cl), so 2 moles of KCl have a mass of about 149 g (2 moles * 74.55 g/mol).