Asked by Rachel Bormann on Jun 24, 2024

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How many days would it take for $9,500 to grow to $10,000 at 7%?

A) 75
B) 188
C) 261
D) 365
E) 275

Grow Amount

The process of increasing the size or value of something, often related to investments or savings over time.

Simple Interest

A financial calculation approach where interest is only derived from the base amount, not including any interest that has built up over time.

  • Compute the period needed for an investment to attain a specified sum, factoring in the interest rate.
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shivkant tiwariJun 26, 2024
Final Answer :
E
Explanation :
To find the number of days it would take for $9,500 to grow to $10,000 at an annual interest rate of 7%, we can use the formula for simple interest: I=PrtI = PrtI=Prt , where III is the interest earned, PPP is the principal amount, rrr is the annual interest rate (as a decimal), and ttt is the time in years. We rearrange the formula to solve for ttt : t=IPrt = \frac{I}{Pr}t=PrI .First, we calculate the interest earned, I=$10,000−$9,500=$500I = \$10,000 - \$9,500 = \$500I=$10,000$9,500=$500 .Next, we convert the annual interest rate to a decimal: r=7%=0.07r = 7\% = 0.07r=7%=0.07 .Then, we plug the values into the rearranged formula: t=$500$9,500×0.07=500665≈0.7519t = \frac{\$500}{\$9,500 \times 0.07} = \frac{500}{665} \approx 0.7519t=$9,500×0.07$500=6655000.7519 years.Finally, to convert years to days, we multiply by 365: 0.7519×365≈274.440.7519 \times 365 \approx 274.440.7519×365274.44 days, which rounds to 275 days.