Glucose has a specific rotation of +52.8°. Predict the concentration of a glucose aqueous solution contained in a 10 cm long polarimetry tube if a rotation of +15.8° was observed.

A) 0.299 g/mL
B) 0299 g/mL
C) 3.34 g/mL
D) 334 g/mL

Question

dbzMASTER HUGHES · Accepted Answer

Final Answer : A, Explanation :   The specific rotation   [ α ] [\alpha] [ α ]   of a substance is related to the observed rotation   α \alpha α  , the concentration   c c c   in grams per milliliter (g/mL), and the path length   l l l   in decimeters (dm) by the formula   [ α ] = α l ⋅ c [\alpha] = \frac{\alpha}{l \cdot c} [ α ] = l ⋅ c α ​  . Given   [ α ] = + 52.8 ° [\alpha] = +52.8° [ α ] = + 52.8°  ,   α = + 15.8 ° \alpha = +15.8° α = + 15.8°  , and   l = 10 c m = 1 d m l = 10 cm = 1 dm l = 10 c m = 1 d m  , we can solve for   c c c  :   c = α [ α ] ⋅ l = 15.8 52.8 ⋅ 1 = 0.299 g / m L c = \frac{\alpha}{[\alpha] \cdot l} = \frac{15.8}{52.8 \cdot 1} = 0.299 g/mL c = [ α ] ⋅ l α ​ = 52.8 ⋅ 1 15.8 ​ = 0.299 g / m L  .

Glucose has a specific rotation of +52.8°. Predict the concentration of a glucose aqueous solution contained in a 10 cm long polarimetry tube if a rotation of +15.8° was observed.

A) 0.299 g/mL
B) 0299 g/mL
C) 3.34 g/mL
D) 334 g/mL

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Learning Objectives

Related questions

Glucose has a specific rotation of +52.8°. Predict the concentration of a glucose aqueous solution contained in a 10 cm long polarimetry tube if a rotation of +15.8° was observed.A) 0.299 g/mLB) 0299 g/mLC) 3.34 g/mLD) 334 g/mL

Definitions

Learning Objectives

Learning Objectives

Related questions

Glucose has a specific rotation of +52.8°. Predict the concentration of a glucose aqueous solution contained in a 10 cm long polarimetry tube if a rotation of +15.8° was observed.

A) 0.299 g/mL
B) 0299 g/mL
C) 3.34 g/mL
D) 334 g/mL