Asked by Jessica Slate on Jun 11, 2024
Verified
Given the following feasible solution determine if the problem is degenerate and then find the optimal solution and its cost. Assume that capacity for source A is 10 and 30 for source B. Destination A demands 10 units while destination B demands 30 units. Cost of shipping per unit is given as AA ($4), AB ($1), BA ($3), and BB ($2).
Destination A Destination B Source A 10 Source B 30\begin{array} { | l | c | c | } \hline & \text { Destination A } & \text { Destination B } \\\hline \text { Source A } & 10 & \\\hline \text { Source B } & & 30 \\\hline\end{array} Source A Source B Destination A 10 Destination B 30
Degenerate
In mathematics and physics, it refers to a less general or simpler class of an entity or phenomenon with less symmetry or fewer distinctions.
Optimal Solution
An Optimal Solution refers to the best possible outcome or decision from a set of alternatives, often identified through processes like optimization in mathematics and computer science.
- Differentiate between possible and best solutions in issues related to transportation.
- Assess improvement indexes and discern the most favorable solutions.
Verified Answer
AH
Ahmed H MohammedJun 14, 2024
Final Answer :
The number of cells used should be 4 - 1 = 3, however only 2 cells are used. Thus the problem is degenerate. Students may then place a zero in either empty cell and proceed with the stepping-stone method to find an optimal solution of
Destination A Destination B Source A 10 Source B 1020\begin{array} { | l | c | c | } \hline & \text { Destination A } & \text { Destination B } \\\hline \text { Source A } & & 10 \\\hline \text { Source B } & 10 & 20 \\\hline\end{array} Source A Source B Destination A 10 Destination B 1020 This solution has a total cost of 10 * 3 + 10 * 1 + 20 * 2 = $80 (compared to $100 from the initial solution).
Destination A Destination B Source A 10 Source B 1020\begin{array} { | l | c | c | } \hline & \text { Destination A } & \text { Destination B } \\\hline \text { Source A } & & 10 \\\hline \text { Source B } & 10 & 20 \\\hline\end{array} Source A Source B Destination A 10 Destination B 1020 This solution has a total cost of 10 * 3 + 10 * 1 + 20 * 2 = $80 (compared to $100 from the initial solution).
Learning Objectives
- Differentiate between possible and best solutions in issues related to transportation.
- Assess improvement indexes and discern the most favorable solutions.
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