Asked by Amina Hussein on May 19, 2024

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Find the n th partial sum of the arithmetic sequence. 8,13,18,23,28,…,n=128,13,18,23,28 , \ldots , n = 128,13,18,23,28,,n=12

A) 390
B) 438
C) 426
D) 354
E) 402

Arithmetic Sequence

An ordered series of numbers where each number following the initial one is derived by adding a fixed difference to the term before it.

Nth Partial Sum

The sum of the first n terms in a sequence, often used in the context of series.

  • Implement formulas for arithmetic sequences to determine designated terms and aggregate sums.
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SH
Sakiko HaradaMay 22, 2024
Final Answer :
C
Explanation :
The common difference between consecutive terms is $13-8=5$. Therefore, the $n$th term is equal to $8 + 5(n-1)$. To find the sum of the first 12 terms, we use the formula for the sum of an arithmetic series:
S12=122(8+(8+5(12−1)))=6(8+59)=426S_{12}=\frac{12}{2}(8+(8+5(12-1))) = 6(8+59) = 426S12=212(8+(8+5(121)))=6(8+59)=426
Thus, the correct choice is $\boxed{\textbf{(C)}}$.