Fill in the blank in the following reaction: $}_{7}^{14} \mathrm{~N}$ + $}_{2}^{4} \mathrm{He}$ ?
$}_{1}^{1} \mathrm{H}$ + ___.

A) $}_{9}^{16} \mathrm{O}$
B) $}_{9}^{16} \mathrm{~N}$
C) $}_{8}^{17} \mathrm{~N}$
D) $}_{8}^{17} \mathrm{O}$

Question

Fill in the blank in the following reaction:   7 14   N { }_{7}^{14} \mathrm{~N} 7 14 ​   N   +   2 4 H e { }_{2}^{4} \mathrm{He} 2 4 ​ He   ? 1 1 H { }_{1}^{1} \mathrm{H} 1 1 ​ H   + ___.A)    9 16 O { }_{9}^{16} \mathrm{O} 9 16 ​ O B)    9 16   N { }_{9}^{16} \mathrm{~N} 9 16 ​   N C)    8 17   N { }_{8}^{17} \mathrm{~N} 8 17 ​   N D)    8 17 O { }_{8}^{17} \mathrm{O} 8 17 ​ O

angelica sanchez · Accepted Answer

Final Answer : D, Explanation :   The sum of the atomic numbers (protons) and mass numbers (protons + neutrons) on both sides of the equation must be equal. Adding the atomic numbers: 7 (nitrogen) + 2 (helium) = 1 (hydrogen) + 8 (oxygen), and the mass numbers: 14 (nitrogen) + 4 (helium) = 1 (hydrogen) + 17 (oxygen), leads to the product being   8 17 O { }_{8}^{17} \mathrm{O} 8 17 ​ O  .

Fill in the blank in the following reaction: $}_{7}^{14} \mathrm{~N}$ + $}_{2}^{4} \mathrm{He}$ ?
$}_{1}^{1} \mathrm{H}$ + ___.

A) $}_{9}^{16} \mathrm{O}$
B) $}_{9}^{16} \mathrm{~N}$
C) $}_{8}^{17} \mathrm{~N}$
D) $}_{8}^{17} \mathrm{O}$

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