Evaluate and simplify f ( x ) = x x + 2 f ( x ) = \frac { x } { x + 2 } f ( x ) = x + 2 x at x=4 .A) f ( 4 ) = − 2 3 f ( 4 ) = - \frac { 2 } { 3 } f ( 4 ) = − 3 2 B) f ( 4 ) = 1 3 f ( 4 ) = \frac { 1 } { 3 } f ( 4 ) = 3 1 C) f ( 4 ) = 2 3 f ( 4 ) = \frac { 2 } { 3 } f ( 4 ) = 3 2 D) f ( 4 ) = 3 2 f ( 4 ) = \frac { 3 } { 2 } f ( 4 ) = 2 3 E) f ( 4 ) = − 3 2 f ( 4 ) = - \frac { 3 } { 2 } f ( 4 ) = − 2 3

Question

Evaluate and simplify   f ( x )  = x x + 2 f ( x )  = \frac { x } { x + 2 } f ( x )  = x + 2 x ​   at x=4 .A)    f ( 4 )  = − 2 3 f ( 4 )  = - \frac { 2 } { 3 } f ( 4 )  = − 3 2 ​ B)    f ( 4 )  = 1 3 f ( 4 )  = \frac { 1 } { 3 } f ( 4 )  = 3 1 ​ C)    f ( 4 )  = 2 3 f ( 4 )  = \frac { 2 } { 3 } f ( 4 )  = 3 2 ​ D)    f ( 4 )  = 3 2 f ( 4 )  = \frac { 3 } { 2 } f ( 4 )  = 2 3 ​ E)    f ( 4 )  = − 3 2 f ( 4 )  = - \frac { 3 } { 2 } f ( 4 )  = − 2 3 ​

Paola Pocop · Accepted Answer

Final Answer : C, Explanation :   Substituting x=4 into the function   f ( x ) = x x + 2 f(x) = \frac{x}{x+2} f ( x ) = x + 2 x ​   gives   f ( 4 ) = 4 4 + 2 = 4 6 = 2 3 f(4) = \frac{4}{4+2} = \frac{4}{6} = \frac{2}{3} f ( 4 ) = 4 + 2 4 ​ = 6 4 ​ = 3 2 ​  .

Evaluate and simplify $\frac { x } { x + 2 }$ at x=4 .

A) $\frac { 2 } { 3 }$
B) $\frac { 1 } { 3 }$
C) $\frac { 2 } { 3 }$
D) $\frac { 3 } { 2 }$
E) $\frac { 3 } { 2 }$

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