A wye-connected alternator that has phase voltages of 277 V is feeding two loads. The first load is wye-connected inductors that have 40 Ω of X_L. The second load is delta-connected capacitors that have X_C of 60 Ω . How much is the alternator phase current?

A) 6.93 A
B) 14.93 A
C) 24.62 A
D) 28 A

The alternator phase current is calculated by dividing the phase voltage by the total impedance seen by the alternator. For the wye-connected load, the impedance is directly 40 Ω. For the delta-connected load, the equivalent wye impedance is one-third of 60 Ω, which is 20 Ω. The total impedance seen by the alternator is 40 Ω + 20 Ω = 60 Ω. The phase current is then 277 V / 60 Ω = 4.62 A. However, this calculation mistake led to an incorrect interpretation. Correctly, for the wye-connected inductors, the current is I = V/Z = 277V / 40Ω = 6.93 A. The delta-connected capacitors do not directly affect the phase current calculation in this manner, as the question asks for the alternator phase current, which is determined by the wye-connected load.