A square wave voltage varies between 0 V and 12 V. The positive pulses are 50 μ s wide and there is a 50 μ s gap between them. What is the DC average of the waveform?

A) 3 V
B) 4 V
C) 6 V
D) 9 V

Question

A square wave voltage varies between 0 V and 12 V. The positive pulses are 50 μ s wide and there is a 50 μ s gap between them. What is the DC average of the waveform?A)  3 VB)  4 VC)  6 VD)  9 V

Zybrea Knight · Accepted Answer

Final Answer : C, Explanation :   The DC average voltage of a square wave can be calculated using the formula:   V a v g = V p e a k × T o n T o n + T o f f V_{avg} = V_{peak} 	imes \frac{T_{on}}{T_{on} + T_{off}} V a vg ​ = V p e ak ​ × T o n ​ + T o ff ​ T o n ​ ​  , where   V p e a k V_{peak} V p e ak ​   is the peak voltage,   T o n T_{on} T o n ​   is the duration the voltage is at   V p e a k V_{peak} V p e ak ​  , and   T o f f T_{off} T o ff ​   is the duration the voltage is at 0V. Given   V p e a k = 12 V V_{peak} = 12V V p e ak ​ = 12 V  ,   T o n = 50 μ s T_{on} = 50 \mu s T o n ​ = 50 μ s  , and   T o f f = 50 μ s T_{off} = 50 \mu s T o ff ​ = 50 μ s  , the DC average is   12 V × 50 50 + 50 = 6 V 12V 	imes \frac{50}{50+50} = 6V 12 V × 50 + 50 50 ​ = 6 V  .

A square wave voltage varies between 0 V and 12 V. The positive pulses are 50 μ s wide and there is a 50 μ s gap between them. What is the DC average of the waveform?

A) 3 V
B) 4 V
C) 6 V
D) 9 V

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