Asked by Joseph Smith on Apr 26, 2024

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A scientist collects data to predict the wheat yield (in bushels per acre) based on rainfall (in millimetres) .The results are recorded in the table below.  Rainfall (mm)  Wheat Yield  (bushels per acre)  11.561.27.625.811.250.61878.58.640.910.542.314.770.413.154\begin{array} { c | c } \begin{array} { c } \text { Rainfall } \\( \mathrm { mm } ) \end{array} & \begin{array} { c } \text { Wheat Yield } \\\text { (bushels per acre) }\end{array} \\\hline 11.5 & 61.2 \\7.6 & 25.8 \\11.2 & 50.6 \\18 & 78.5 \\8.6 & 40.9 \\10.5 & 42.3 \\14.7 & 70.4 \\13.1 & 54\end{array} Rainfall (mm) 11.57.611.2188.610.514.713.1 Wheat Yield  (bushels per acre)  61.225.850.678.540.942.370.454 Compute Spearman's rank correlation.Assume that rank ties will have little influence on your result.

A) 0.962
B) 0.944
C) 0.976
D) 0.94
E) 0.942

Spearman's Rank Correlation

A measure that does not rely on parameters, used to determine the correlation in ranking, and assesses the ability to explain the relationship between two variables with a monotonic function.

Wheat Yield

The amount of wheat produced per unit area, commonly measured in bushels per acre or kilograms per hectare.

Rainfall

The total amount of rain that falls in a specific area over a specific period, often measured in millimeters or inches.

  • Develop competencies in utilizing and deciphering Spearman's rank correlation for evaluating the association's intensity between two variables.
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SS
Shiri ShaheidApr 30, 2024
Final Answer :
C
Explanation :
Spearman's rank correlation coefficient is given by the formula:
rs=1−6∑d2n(n2−1)r_s=1-\frac{6\sum{d^2}}{n(n^2-1)}rs=1n(n21)6d2
where $d$ is the difference in ranks and $n$ is the sample size. We can first rank the data in order of increasing rainfall and wheat yield:
 Rank  Rainfall  Rainfall (mm) Rank  Yield  Yield  ( bushels per acre ) 17.6125.828.6440.9310.5542.3411.2250.6511.5761.2613.1654714.7870.4818978.5\begin{array} { c | c | c | c } \begin{array}{c} \text { Rank } \\\text { Rainfall }\end{array} & \begin{array}{c} \text { Rainfall } \\( \mathrm { mm } )\end{array}&\begin{array}{c} \text { Rank } \\\text { Yield }\end{array} & \begin{array}{c} \text { Yield } \\\text { ( bushels per acre ) }\end{array} \\\hline 1 & 7.6 &1 &25.8 \\2 & 8.6 & 4 &40.9 \\3 & 10.5 & 5 &42.3 \\4 & 11.2 & 2 &50.6 \\5 & 11.5 & 7 &61.2 \\6 & 13.1 & 6 &54 \\7 & 14.7 & 8 &70.4 \\8 & 18 & 9 &78.5 \\\end{array} Rank  Rainfall 12345678 Rainfall (mm)7.68.610.511.211.513.114.718 Rank  Yield 14527689 Yield  ( bushels per acre ) 25.840.942.350.661.25470.478.5
Then we calculate the differences in ranks, $d$, and $d^2$:
 Rank  Rainfall  Rainfall (mm) Rank  Yield  Yield  (bushels per acre) d217.6125.8028.6440.94310.5542.34411.2250.64511.5761.24613.16540714.7870.41818978.59\begin{array} { c | c | c | c | c } \begin{array}{c} \text { Rank } \\\text { Rainfall }\end{array} & \begin{array}{c} \text { Rainfall } \\( \mathrm { mm } )\end{array}&\begin{array}{c} \text { Rank } \\\text { Yield }\end{array} & \begin{array}{c} \text { Yield } \\\text { (bushels per acre) }\end{array} &d^2 \\\hline 1 & 7.6 &1 &25.8 & 0 \\2 & 8.6 & 4 &40.9 & 4 \\3 & 10.5 & 5 &42.3 & 4 \\4 & 11.2 & 2 &50.6 & 4 \\5 & 11.5 & 7 &61.2 & 4 \\6 & 13.1 & 6 &54 & 0 \\7 & 14.7 & 8 &70.4 & 1 \\8 & 18 & 9 &78.5 & 9 \\\end{array} Rank  Rainfall 12345678 Rainfall (mm)7.68.610.511.211.513.114.718 Rank  Yield 14527689 Yield  (bushels per acre) 25.840.942.350.661.25470.478.5d204444019
Summing the $d^2$ column, we get $\sum{d^2}=26$. Plugging into the formula for $r_s$, we have $r_s=1-\frac{6(26)}{8(8^2-1)}=0.976$. Therefore, the best choice is (C).