Asked by Sydnee Smith on May 10, 2024

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A random sample of 25,000 ACT test takers had an average score of 21 with a standard deviation of 5.With a .95 probability, determine the margin of error.

A) .0277
B) .0568
C) .2603
D) .0620

Margin of Error

Indicates the confidence in the precision of a survey or poll result, quantifying potential deviation from the true population value.

Standard Deviation

An indicator of the range or distribution of a data set, showing the degree to which the values diverge from the average.

ACT Test Takers

Individuals who participate in taking the ACT, a standardized test used for college admissions in the United States.

  • Appreciate the influence of sample size and confidence levels on the accuracy of the margin of error and the formulation of confidence intervals for population means and proportions.
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RL
Ricardo LanderosMay 15, 2024
Final Answer :
D
Explanation :
The formula for the margin of error is:
Margin of error = z * (standard deviation / sqrt(sample size))
We need to find the z-value corresponding to a .95 probability. This is the same as finding the z-value that leaves .025 in the upper tail of the standard normal distribution. Using a z-table, we find that z = 1.96.

Plugging in the values,
Margin of error = 1.96 * (5 / sqrt(25000))
Margin of error = 0.062

Therefore, the margin of error is 0.062 or approximately 0.06. So the correct answer is D.