Asked by Paige Gratton on Jul 22, 2024
Verified
A manufacturing firm wants to apply 6-sigma standards to its automated tolerance-check process. Suppose that each scanner makes the correct decision only 39% of the time, however only 1 correct decision by any scanner makes the entire process a success. The firm uses 12 scanners, does this ensure 6-sigma quality?
6-Sigma Standards
A set of techniques and tools for process improvement, aiming at reducing defects and variability in manufacturing and business processes to improve quality.
Automated Tolerance-Check
A computerized process for verifying if manufactured parts fall within specified tolerance levels.
- Describe and determine the reliability of a multi-component system.
- Comprehend the principle of product reliability and the factors that influence it.
Verified Answer
FC
Florence CelestinoJul 23, 2024
Final Answer :
Number of breakdowns 012345 Total Breakdown frequency .10.10.10.30.35.051.00\begin{array} { | l | c | c | c | c | c | c | c | } \hline \text { Number of breakdowns } & 0 & 1 & 2 & 3 & 4 & 5 & \text { Total } \\\hline \text { Breakdown frequency } & .10 & .10 & .10 & .30 & .35 & .05 & 1.00 \\\hline\end{array} Number of breakdowns Breakdown frequency 0.101.102.103.304.355.05 Total 1.00 Expected number of breakdowns = (0 ∗ .10) + (1 ∗ .10) + (2 ∗ .10) + (3 ∗ .30) + (4 ∗ .35) +
(5 ∗ .05) = 2.85; Expected cost of breakdowns per month = 2.85 ∗ $3,000 = $8,550; Cost of preventive maintenance = (1 ∗ $3,000) + $500 = $3,500. It is about three times more expensive to suffer breakdowns than to perform preventive maintenance.
(5 ∗ .05) = 2.85; Expected cost of breakdowns per month = 2.85 ∗ $3,000 = $8,550; Cost of preventive maintenance = (1 ∗ $3,000) + $500 = $3,500. It is about three times more expensive to suffer breakdowns than to perform preventive maintenance.
Learning Objectives
- Describe and determine the reliability of a multi-component system.
- Comprehend the principle of product reliability and the factors that influence it.