A dietician is asked to design a special diet supplement using two foods. Each ounce of food X contains 31 units of calcium and each ounce of food Y contains 20 units of calcium. The minimum daily requirement in the diet is 300 units of calcium. Write a linear inequality that represents the different numbers of units of food X and food Y required.A) 31 X + 20 Y ≥ 300 31 X + 20 Y \geq 300 31 X + 20 Y ≥ 300 B) 20 X + 31 Y ≥ 300 20 X + 31 Y \geq 300 20 X + 31 Y ≥ 300 C) 31 X − 20 Y ≥ 300 31 X - 20 Y \geq 300 31 X − 20 Y ≥ 300 D) 31 X + 20 Y ≥ 249 31 X + 20 Y \geq 249 31 X + 20 Y ≥ 249 E) 11 X + 20 Y ≥ 300 11 X + 20 Y \geq 300 11 X + 20 Y ≥ 300

Question

A dietician is asked to design a special diet supplement using two foods. Each ounce of food X contains 31 units of calcium and each ounce of food Y contains 20 units of calcium. The minimum daily requirement in the diet is 300 units of calcium. Write a linear inequality that represents the different numbers of units of food X and food Y required.A)    31 X + 20 Y ≥ 300 31 X + 20 Y \geq 300 31 X + 20 Y ≥ 300 B)    20 X + 31 Y ≥ 300 20 X + 31 Y \geq 300 20 X + 31 Y ≥ 300 C)    31 X − 20 Y ≥ 300 31 X - 20 Y \geq 300 31 X − 20 Y ≥ 300 D)    31 X + 20 Y ≥ 249 31 X + 20 Y \geq 249 31 X + 20 Y ≥ 249 E)    11 X + 20 Y ≥ 300 11 X + 20 Y \geq 300 11 X + 20 Y ≥ 300

james Barrionuevo · Accepted Answer

Final Answer : A, Explanation :  Since each ounce of food X contains 31 units of calcium and each ounce of food Y contains 20 units of calcium, we can create the following inequality:31X + 20Y ≥ 300This inequality ensures that the diet contains at least 300 units of calcium by combining the amounts of calcium from both foods X and Y.

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